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From the middle figure below we see that the front part of the 747 has
crossed the intersection and there is 25 more meters to go before the
tail crosses over the intersection. The plane is regarded as being in the
intersection so long as any part of the plane extends into the space of
the intersction. For the nose of the plane to get to the point it is now
it traveled a distance of 57 m from when it was just touching the left
side of the intersection
Before
____
____/ |\_
============\
=====>______/
\____|> \
UU OO
---------|==========|----------------|-----
0m 25m 57m
Intersection
During
--- ____
\ \_______________/ |\_
<==========================\
-----_____<=====>______/
\____|> \
UU OO
---------|==========|----------------|-----
0m 25m 57m
Intersection
After
--- ____
\ \_______________/ |\_
<==========================\
-----_____<=====>______/
\____|> \
UU OO
---------|==========|----------------|-----
0m 25m 57m
Intersection
The tail has to now travel adistance of 25 m to clear the
intersection which during this time the nose also travels forward another
25 meters.the plane has thus traveled an total of 57 m +25 m = 82m
The equation which relates velocity to acceleration and displacement is
(1) v^2 = vo^2 +2ad
Where d is the displacement, v and vo are the final and initial
velocities and a is the acceleration. Solving (1) for vo gives
(2) vo^2 = v^2 - 2ad
so
(3) vo =sqrt(v^2 - 2ad)
substitution of v = 45 m/s, a = -5.7m/s^2 and d = 82 m gives
(4) vo =sqrt((45 m/s)^2 - 2(-5.7m/s^2)82 m) = 54.4 m/s
Next displacement is related to time by
(4) d = do + vo t + (1/2)a t^2
Here do =0m, d =82m, vo=54.4m, and a=-5.7m so
(5) 82m = (54.4m/s)t - (2.85m/s^2) t^2
or
(6) (2.85m/s^2) t^2 - (54.4m/s)t +82m = 0m
Applying the quadratic formula to
(7) 2.85 t^2 - 54.4m/s t +82 = 0
gives
(8) -(-54.4) +/-sqrt((-54.4)^2 - 4(2.85)82)
t = ----------------------------------------
2(2.85)
54.4 +/-sqrt(2959.36 - 934.8)
= -------------------------------
5.7
54.4 +/-45.0
= ---------------
5.7
= (17.5, 1.6)
We take the smaller value because the plane does not cross the
intersection, stop and then reverse its course and cross again! Only the
first crossing counts. Thus
************
* *
* t = 1.6s *
* *
************
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