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Suppose that two parallel wires carry current in the same direction.
We find the force on wire 2 due to the field generated by wire 1. By the
right hand rule the magnetic field due to wire 1 comes out of the plane of
the page above wire 1 in the figure below and into the plane of the page
below it
->
. . . . . . . . . . . B1 out here
-----------------------------------> wire 1 current I1
->
X X X X X X X X X X X B1 into page here
-----------------------------------> wire 2 current I2
->
L ------> directed length in this direction
So wire 2 sees a b field into the plane of the page at right angles to the
plane of the page. Now the force on wire 2 due to B1 is
-> -> ->
(1) F = I2 L x B1
->
Where L is the directed length of wire 2 in the direction of the current
in wire 2. By the right hand rule
-> ->
L x B1 is towards wire 1. Therefore the wires are attracted.
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