phillip passero
asks:
CATAGORY: Electricity & Magnetism
QUESTION: A resistor, a capacitor, and a inductor are connected in series
across a 60.0-Hz, 120-V a-c source. The resistance is 18.0-ohms, the
capacitive reactance is 8.0-ohms, and the inductive reactance is
12.0-ohms. Calculate the impedance.
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The impedance is given by
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(1) Z = \/ R^2 +(X(L) -X(C))^2
Where R is the resistance, X(L) is the reactance of the
inductor and X(C) is the reactance of the capacitor.
thus
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(2) Z = \/ 18.0^2 +(12.0 -8.0)^2 [ohms]
= 18.44 ohms
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* *
* Z = 18.44 ohms *
* *
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